4.8=5t^2

Solution for 4.8=5t^2 equation:

4.8=5t^2

We move all terms to the left:

4.8-(5t^2)=0

a = -5; b = 0; c = +4.8;
Δ = b2-4ac
Δ = 02-4·(-5)·4.8
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*-5}=\frac{0-4\sqrt{6}}{-10}
=-\frac{4\sqrt{6}}{-10}
=-\frac{2\sqrt{6}}{-5}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*-5}=\frac{0+4\sqrt{6}}{-10}
=\frac{4\sqrt{6}}{-10}
=\frac{2\sqrt{6}}{-5}
$